If 15 men can complete a piece of work in 20 days, how many days will be taken by 25 men to complete the same work?

Question

Accepted Answer

This is an inverse proportion problem involving men and days (more men mean fewer days required).

### Formula:
$$M_1 	imes D_1 = M_2 	imes D_2$$
Where:
* $M_1 = 15 	ext{ men}$
* $D_1 = 20 	ext{ days}$
* $M_2 = 25 	ext{ men}$
* $D_2 = ?$

### Step-by-Step Solution:
1. Set up the equation:
   $$15 	imes 20 = 25 	imes D_2$$
2. Solve for $D_2$:
   $$300 = 25 	imes D_2$$
   $$D_2 = \frac{300}{25} = 12 	ext{ days}$$

**Answer:** 25 men will complete the work in **12 days**.

If 15 men can complete a piece of work in 20 days, how many days will be taken by 25 men to complete the same work? - DDCET Q&A

If 15 men can complete a piece of work in 20 days, how many days will be taken by 25 men to complete the same work?

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